215 = 32768 and the sum of its digits is 3 + 2 + 7 + 6 + 8 = 26.
What is the sum of the digits of the number 21000?
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j=0
i=10
while 10*n>i:
if n%i >= i/10:
j= j + first(n-(n/i)*i)
else:
j=j
i=10*i
return j
def first(n):
j=1
i=1
while n > i:
j=n/i
i = 10*i
return j
print sumd(2**1000)
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